73x^2-24x-441=0

Solution for 73x^2-24x-441=0 equation:

73x^2-24x-441=0

a = 73; b = -24; c = -441;
Δ = b2-4ac
Δ = -242-4·73·(-441)
Δ = 129348
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{129348}=\sqrt{36*3593}=\sqrt{36}*\sqrt{3593}=6\sqrt{3593}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-6\sqrt{3593}}{2*73}=\frac{24-6\sqrt{3593}}{146}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+6\sqrt{3593}}{2*73}=\frac{24+6\sqrt{3593}}{146}
$